If ∫ e sin ⁡ θ sin ⁡ θ + sec 2 ⁡ θ d θ is equal to f θ + C (where, C is the constant of integration) and f 0 = 0 , then the value of f π 4 is

Question

If ∫ e sin ⁡ θ sin ⁡ θ + sec 2 ⁡ θ d θ is equal to f θ + C (where, C is the constant of integration) and f 0 = 0 , then the value of f π 4 is, e 2, e 1 2, e 2, e 1 2

MARKS App · Accepted Answer

∫ e sin ⁡ θ sin ⁡ θ d θ + ∫ e sin ⁡ θ sec 2 ⁡ θ d θ ∫ e sin ⁡ θ sin ⁡ θ d θ + tan ⁡ θ e sin ⁡ θ - ∫ tan ⁡ θ e sin ⁡ θ cos ⁡ θ d θ = ∫ e sin ⁡ θ sin ⁡ θ d θ + tan ⁡ θ e sin ⁡ θ - ∫ e sin ⁡ θ sin ⁡ θ d θ = e sin ⁡ θ tan ⁡ θ + C = e sin ⁡ θ tan ⁡ θ + C f θ = e sin ⁡ θ tan ⁡ θ f π 4 = e 1 2

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