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If \(E_c\) and \(E_m\) are peak values of carrier and modulating signals, respectively then for \(100 \%\) modulation,
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Verified Answer
The correct answer is:
\(E_{\mathrm{c}}=E_m\)
Key idea Modulation index of a modulated signal is
\(\mu=\frac{E_m}{E_c}\)
Where, \(E_m\) and \(E_c\) are peak values of modulating signal and carrier signal.
For \(100 \%\) modulation, modulation index should be unity.
Hence, \(\mu=1=\frac{E_m}{E_c}\)
\(\Rightarrow \quad E_m=E_c\)
\(\therefore\) The correct option is (c).
\(\mu=\frac{E_m}{E_c}\)
Where, \(E_m\) and \(E_c\) are peak values of modulating signal and carrier signal.
For \(100 \%\) modulation, modulation index should be unity.
Hence, \(\mu=1=\frac{E_m}{E_c}\)
\(\Rightarrow \quad E_m=E_c\)
\(\therefore\) The correct option is (c).
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