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If eight coins are tossed simultaneously, then the probability of getting atleast six heads is
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Verified Answer
The correct answer is:
$\frac{37}{256}$
Since 8 coins are tossed simultaneously. Hence total samples $=2^8=256=n(\mathrm{~S})$ Number of ways of getting at least 6 heads $={ }^8 c_6+{ }^8 c_7+{ }^8 c_8=37=n(\mathrm{E})$
Therefore,
Required probability $=\frac{n(\mathrm{E})}{n(\mathrm{~S})}=\frac{37}{256}$
Therefore,
Required probability $=\frac{n(\mathrm{E})}{n(\mathrm{~S})}=\frac{37}{256}$
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