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If $f:[0, \infty) \rightarrow[0, \infty)$ and $f(x)=\frac{x}{1+x}$, then $f$ is
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One-one but not onto
$f^{\prime}(x)=\frac{1}{(1+x)^2}\gt0, \forall x \in[0, \infty)$ and range $\in[0,1)$ $\Rightarrow$ function is one-one but not onto.
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