Search any question & find its solution
Question:
Answered & Verified by Expert
If $F_e$ and $F_e$ are the focal length of the objective and eye-piece respectively of a telescope, then its magnifying power will be
Options:
Solution:
1261 Upvotes
Verified Answer
The correct answer is:
$F_o / F_e$
Correct option is $3$
$m=\frac{\mathrm{f}_0}{\mathrm{f}_{\mathrm{e}}}$
$m=\frac{\mathrm{f}_0}{\mathrm{f}_{\mathrm{e}}}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.