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If $f: R \rightarrow R$ be defined by $f(x)=\left\{\begin{array}{lcc}2 x & : & x>3 \\ x^2 & : & 1 < x \leq 3 \\ 3 x & : & x \leq 1\end{array}\right.$ then $f(-1)+f(2)+f(4)$ is
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The correct answer is:
9
$f(x)=\left\{\begin{array}{ccc}2 x & : & x>3 \\ x^2 & : & 1 < x \leq 3 \\ 3 x & : & x \leq 1\end{array}\right.$
$$
\begin{aligned}
f(-1)+f(2)+f(4) & =3(-1)+(2)^2+2(4) \\
& =-3+4+8=9
\end{aligned}
$$
$$
\begin{aligned}
f(-1)+f(2)+f(4) & =3(-1)+(2)^2+2(4) \\
& =-3+4+8=9
\end{aligned}
$$
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