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Question: Answered & Verified by Expert
If $f: R \rightarrow R$ is defined by $f(x)=x^{3}$, then $f^{-1}(8)=$
MathematicsFunctionsCOMEDKCOMEDK 2019
Options:
  • A $\{2\}$
  • B $\left\{2,2 \omega, 2 \omega^{2}\right\}$
  • C $\{2,2\}$
  • D $\{2,2\}$
Solution:
1060 Upvotes Verified Answer
The correct answer is: $\{2\}$
Let $f^{-1}(8)=x$
$$
\begin{array}{lrlrl}
& \Rightarrow & & f(x) & =8 \\
\Rightarrow & & x^{3} & =8 \\
\Rightarrow & & x & =2 \\
& \therefore & & f^{-1}(8) & =\{2\}
\end{array}
$$
$$
\Rightarrow \quad x=2 \quad[\because x \in R]
$$

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