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If $f(x)=\left|\begin{array}{ccc}(1+x)^{17} & (1+x)^{19} & (1+x)^{23} \\ (1+x)^{23} & (1+x)^{29} & (1+x)^{34} \\ (1+x)^{41} & (1+x)^{43} & (1+x)^{47}\end{array}\right|$ $=\mathrm{A}+\mathrm{Bx}+\mathrm{Cx}{ }^2+\ldots \ldots$, then $\mathrm{A}=$
MathematicsDeterminants
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Zero

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