Search any question & find its solution
Question:
Answered & Verified by Expert
If $f(x)=\left\{\begin{array}{l}1+x^2, \text { when } 0 \leq x \leq 1 \\ 1-x, \text { when } x\gt1\end{array}\right.$, then
Options:
Solution:
2888 Upvotes
Verified Answer
The correct answer is:
$f(x)$ is discontinuous at $x=1$
$\lim _{x \rightarrow 1^+} f(x)=0$ and $\lim _{x \rightarrow 1^-} f(x)=1+1=2$.
Hence $f(x)$ is discontinuous at $x=1$.
Hence $f(x)$ is discontinuous at $x=1$.
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.