Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If fx2-4x+3>0, x2,3, then gx=fsinx is increasing in
MathematicsApplication of DerivativesJEE Main
Options:
  • A x0,π
  • B x0,π2
  • C xπ,5π4
  • D x3π2,2π
Solution:
1394 Upvotes Verified Answer
The correct answer is: x3π2,2π
x2-4x+3=x-22-1
If x2,3, then x2-4x+3-1,0
Now,  g x = f sinx .cosx
For gx to be increasing
sinx-1,0 and cosx>0
x3π2,2π

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.