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Question: Answered & Verified by Expert
If fx=5x+4tanxx x0k x=0, then fx is continuous at x=0 for
MathematicsContinuity and DifferentiabilityJEE Main
Options:
  • A k=9
  • B k=-1
  • C no values of k
  • D k=2
Solution:
2773 Upvotes Verified Answer
The correct answer is: no values of k
limx0-fx=limx0-5x+4tanxx
=limx0-5-x+4tanxx
=limx0--5xx+limx0-4tanxx
=-5+4=-1
and limx0+fx=limx0+5x+4tanxx
=limx0+5xx+4tanxx
=5+4=9
limx0-fxlimx0+fx
fx is not continuous at x=0, for any value of k 

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