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Question: Answered & Verified by Expert
If fx=a+bcosx+csinxx2;x>09;x0 is continuous at x=0, then the value of a+b5 is
MathematicsContinuity and DifferentiabilityJEE Main
Solution:
1027 Upvotes Verified Answer
The correct answer is: 7.20
For fx to be continuous at x=0
limx0fx=f0
limx0a+bcox+csixx2=9
limx0a+b1-x22!+x24!-....+cx-x33!+x55!-....x2=9
limx0a+b+cx+-b2x2+-c6x3.....x2=9
for the above limit to satisfy
a+b=0,
c=0 and 
-b2=9b=-18, c=0, a=18

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