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If $f(x)=a \cos (x+c)+d$, then range of $f(x)$ is
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2216 Upvotes
Verified Answer
The correct answer is:
$[d-a, d+a]$
$f(x)=a \cos (x+c)+d$ ....(i)
For minimum $\cos (x+c)=-1$
from (i), $f(x)=-a+d=(d-a)$
For maximum $\cos (x+c)=1$
from (i), $f(x)=a+d=(d+a)$
For minimum $\cos (x+c)=-1$
from (i), $f(x)=-a+d=(d-a)$
For maximum $\cos (x+c)=1$
from (i), $f(x)=a+d=(d+a)$
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