If f x = a x 2 + b x + c , f - 1 > 1 2 , f 1 - 1 and f - 3 - 1 2 , then, a = 0, a 0, a > 0, Sign of a can not be determined

Clearly, parabola is opening downwards ⇒ a 0 .

If f x = a x 2 + b x + c , f - 1 > 1 2 , f 1 - 1 and f - 3

Question: Answered & Verified by Expert

f (x) = a x^{2} + b x + c, f (- 1) > \frac{1}{2}, f (1) < - 1

and

f (- 3) < - \frac{1}{2}

, then

MathematicsQuadratic EquationJEE Main

Options:

Solution:

1090 Upvotes Verified Answer

The correct answer is:

a < 0

Clearly, parabola is opening downwards

\Rightarrow a < 0 .

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