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Question: Answered & Verified by Expert
If fx=cosx+sinx and gx=x2-1, then gfx is injective in the interval
MathematicsFunctionsJEE Main
Options:
  • A 0,π2
  • B π4,π4
  • C π2,π2
  • D 0,π
Solution:
2200 Upvotes Verified Answer
The correct answer is: π4,π4
gfx=sinx+cosx2-1=sin2x
Now, sin2x is injective if 2xnπ-π2,nπ+π2
xnπ2-π4,nπ2+π4 nZ

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