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If fx=sinx, gx=cosx and hx=coscosx, then the integral Ι=fgx.fx.hxdx simplifies to -λsin2cosx+C (where, C is the constant of integration). The value of λ is equal to
MathematicsIndefinite IntegrationJEE Main
Solution:
1312 Upvotes Verified Answer
The correct answer is: 0.50
Given integral, Ι=sincosx.sinx.coscosxdx
Let, sincosx=t-coscosx.sinxdx=dt
Ι=-tdt=-t22+C
=C-sin2cosx2

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