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Question: Answered & Verified by Expert
If  fx=sin[x][x],[x]00,[x]=0, where x denotes the greatest integer less than or equal to x, then limx0-fx
MathematicsLimitsTS EAMCETTS EAMCET 2021 (05 Aug Shift 1)
Options:
  • A exist and equal to 1
  • B exist and equal to sin 1
  • C exist and equal to -sin 1
  • D Does not exist
Solution:
1421 Upvotes Verified Answer
The correct answer is: exist and equal to sin 1

limx0-fx

=limx0-sinxx

=sin-1-1, as x=-1,  x-1,0

=sin1

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