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If $f(x)=\left\{\begin{array}{r}x-1, x \lt 0 \\ \frac{1}{4}, x=0 \\ x^2, x\gt0\end{array}\right.$ then
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The correct answer is:
$f(x)$ is discontinuous at $x=0$
Clearly from curve drawn of the given function $f(x)$ is discontinuous at $x=0$.
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