If f x = x + 1 ; x > 1 0 ; x = 1 7 - 3 x ; x 1 then f ′ 0 equals to, - 1, - 2, - 3, - 4

As for x 1 , f x = 7 - 3 x ⇒ f ′ x = - 3 ⇒ f ′ 0 = - 3

If f x = x + 1 ; x > 1 0 ; x = 1 7 - 3 x ; x 1 then f ′ 0 equals to

Question: Answered & Verified by Expert

f (x) = \{\begin{array}{l} x + 1; & x > 1 \\ 0; & x = 1 \\ 7 - 3 x; & x < 1 \end{array}

then

f^{'} (0)

equals to

MathematicsDifferentiationJEE Main

Options:

Solution:

1282 Upvotes Verified Answer

The correct answer is:

- 3

As for

x < 1, f (x) = 7 - 3 x \Rightarrow f^{'} (x) = - 3 \Rightarrow f^{'} (0) = - 3

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