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Question: Answered & Verified by Expert
If $f(x)=|x-1|+|x-2|$, then $f^{\prime}(-2023)+$ $\mathrm{f}^{\prime}\left(\frac{2024}{2023}\right)+\mathrm{f}^{\prime}(2023)=$
MathematicsFunctionsTS EAMCETTS EAMCET 2023 (13 May Shift 1)
Options:
  • A $1$
  • B $-1$
  • C $0$
  • D $3$
Solution:
1338 Upvotes Verified Answer
The correct answer is: $0$
$\begin{aligned} & \text { When } x=-2023 \Rightarrow f(x)=-(x-1)-(x-2)=-2 x+3 \\ & \Rightarrow f^{\prime}(x)=-2 \Rightarrow f^{\prime}(-2023)=-2 \\ & \text { When } x=\frac{2024}{2023} \Rightarrow f(x)=(x-1)-(x-2)=1 \\ & \Rightarrow f^{\prime}(x)=0 \Rightarrow f^{\prime}\left(\frac{2024}{2023}\right)=0 \\ & \text { When } x=2023 \Rightarrow f(x)=(x-1)+(x-2)=2 x-3 \\ & \Rightarrow f^{\prime}(x)=2 \Rightarrow f^{\prime}(2023)=2 \\ & \text { Therefore } f^{\prime}(-2023)+f^{\prime}\left(\frac{2024}{2023}\right)+f^{\prime}(-2023)=0\end{aligned}$

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