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If $f(x)=\left\{\begin{array}{cl}\frac{x^{2}+3 x-10}{x^{2}+2 x-15} & \text { , when } x \neq-5 \\ \text { a }, & \text { when } x=-5\end{array}\right.$
is continuous at $x=-5$, then the value of 'a' will be
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is continuous at $x=-5$, then the value of 'a' will be
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Verified Answer
The correct answer is:
$7 / 8$
$\lim _{x \rightarrow-5} f(x)=\frac{(x-2)(x+5)}{(x+5)(x-3)}=\frac{-7}{-8}=\frac{7}{8}$
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