Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If fx=x2+α for x=2x2+1+β for x<0 is continuous at x=0 and f12=2 then α2+β2 is
MathematicsContinuity and DifferentiabilityMHT CETMHT CET 2018
Options:
  • A 3
  • B 825
  • C 258
  • D 13
Solution:
2794 Upvotes Verified Answer
The correct answer is: 258
lim x 0 + x 2 +α= lim x 0 - 2 x 2 +1 +β
α=2+β.........( 1 )
f( x )= x 2 +α;x0
f( 1 2 )= 1 4 +α
2= 1 4 +α
7 4 =α
7 4 2=β
β = - 1 4
Hence α 2 + β 2 = 49 16 + 1 16 = 50 16 = 25 8

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.