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Question: Answered & Verified by Expert
If fx=x2sin1x, when x0 and f0=0, then limx0f'x
MathematicsLimitsJEE Main
Options:
  • A Does not exist
  • B 0
  • C
  • D 1
Solution:
2507 Upvotes Verified Answer
The correct answer is: Does not exist

limx0f'x

=limx02xsin1x+x2-1x2cos1x

=2limx0xsin1x-limx0cos1x

=0-limx0cos1x

Limit does not exist as value of cos1x oscillatesy between -1 & 1 as x approaches 0.

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