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Question: Answered & Verified by Expert
$$
\text { If } \begin{aligned}
f(x) &=\frac{|x-2|}{x-2}, \quad \text { for } x \neq 2 \\
&=1 \quad, \quad \text { for } x=2,
\end{aligned}
$$
then which of the following statements is true?
MathematicsContinuity and DifferentiabilityMHT CETMHT CET 2020 (15 Oct Shift 1)
Options:
  • A $f(x)$ is continuous at $x=2$
  • B $\lim _{x \rightarrow 2^{-}} f(x)=f(2)$
  • C $\lim _{x \rightarrow 2^{+}} f(x)=\lim _{x \rightarrow 2^{-}} f(x)$
  • D $f(x)$ is discontinuous at $x=2$
Solution:
1717 Upvotes Verified Answer
The correct answer is: $f(x)$ is discontinuous at $x=2$
Here $\begin{aligned}|x-2| &=x-2, \quad \text { if } x>2 \Rightarrow \lim _{x \rightarrow 2^{-}} f(x)=\lim _{x \rightarrow 2^{+}} f(x)=0 \\ &=-(x-2), \text { if } x < 2 \end{aligned}$
But $f(2)=1 \neq 0$
So $f(x)$ is discontinuous at $x=2$

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