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If $f(x)=x^3-x$ and $g(x)=\sin 2 x$, then $f\left(g\left(\frac{\pi}{12}\right)\right)=$
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$-\frac{3}{8}$
$\begin{aligned} & \text { } g\left(\frac{\pi}{12}\right)=\sin ^2\left(\frac{\pi}{12}\right)=\frac{1}{2} \\ & \Rightarrow f\left(g\left(\frac{\pi}{12}\right)\right)=f\left(\frac{1}{2}\right)=\frac{1}{8}-\frac{1}{2}=-\frac{3}{8}\end{aligned}$
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