If f x = x - 4 x - 4 + t a n - 1 1 - 2 x 2 + x , ∀ 4 x 8 , then the value of f ′ 5 is equal to

Question

If f x = x - 4 x - 4 + t a n - 1 1 - 2 x 2 + x , ∀ 4 x 8 , then the value of f ′ 5 is equal to, - 7 13, 0, 5 13, - 8 13

MARKS App · Accepted Answer

f x = x - 4 2 + 2 2 - 2.2 x - 4 + t a n - 1 1 2 - x 1 + 1 2 . x f x = x - 4 - 2 2 + t a n - 1 1 2 - t a n - 1 x f x = 2 - x - 4 + t a n - 1 1 2 - t a n - 1 x ∵ x - 4 2 f ′ x = − 1 2 x − 4 − 1 1 + x 2 f ′ 5 = − 1 2 − 1 1 + 25 = − 14 26 = − 7 13

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