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If $f(x)=x, g(x)=\sin x$, then $\int f(g(x)) d x$ is equal to
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The correct answer is:
$-\cos x+c$
$\begin{aligned} \int f(g(x)) d x &=\int f(\sin x) d x \\ &=\int \sin x d x \\ &=-\cos x+c \end{aligned}$
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