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If $f(x)=|x|/x$ for x≠0 and 1 for X=0, then the function is
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Verified Answer
The correct answer is:
neither continuous nor differentiable at $x=0$
$f(x)=\left\{\begin{array}{cc}
1 & x>0 \\
-1 & x < 0 \\
1 & x=0
\end{array}\right.$
So function discontinuous and non differentiable
1 & x>0 \\
-1 & x < 0 \\
1 & x=0
\end{array}\right.$
So function discontinuous and non differentiable
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