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If frequency of \(R-L\) circuit is \(f\) then impedence will be
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Verified Answer
The correct answer is:
\(\sqrt{R^2+(2 \pi f L)^2}\)
Impedance of $R L$ circuit is
$\begin{gathered}Z=\sqrt{R^2+X_L^2} \\ \text { where } X_L=\omega L=2 \pi f L \\ \therefore Z=\sqrt{R^2+(2 \pi f L)^2}\end{gathered}$
$\begin{gathered}Z=\sqrt{R^2+X_L^2} \\ \text { where } X_L=\omega L=2 \pi f L \\ \therefore Z=\sqrt{R^2+(2 \pi f L)^2}\end{gathered}$
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