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If from $R \rightarrow R, f(x)=(x+1)^2, g(x)=x^2+1$, then $(f \circ g)(-3)$ equals
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$121$
$\begin{aligned} & f(x)=(1+x)^2 \text { and } g(x)=x^2+1 \\ & \text { and } f \circ g(-3)=f[g(-3)]=f[9+1]=f[10] \\ & \Rightarrow f \circ g(-3)=f[10]=[11]^2=121 .\end{aligned}$
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