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If f(x) = sin(cosx) , then f'(x) is equal to ?
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Verified Answer
The correct answer is:
$(-\sin x) \cos (\cos x)$
$\mathrm{f}(\mathrm{x})=\sin (\cos \mathrm{x})$
$\mathrm{f}^{\prime}(\mathrm{x})=\cos (\cos \mathrm{x}) \cdot(-\sin \mathrm{x})$
$=-\sin \mathrm{x} \cdot \cos (\cos \mathrm{x})$
$\mathrm{f}^{\prime}(\mathrm{x})=\cos (\cos \mathrm{x}) \cdot(-\sin \mathrm{x})$
$=-\sin \mathrm{x} \cdot \cos (\cos \mathrm{x})$
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