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If \(f(x)=x^4-x^3+7 x^2+14\), then what is the value of \(f^{\prime}(5)\) ?
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The correct answer is:
495
Since, \(f(x)=x^4-x^3+7 x^2+14\)
Then, \(\quad f^{\prime}(x)=4 x^3-3 x^2+14 x\)
\(\therefore \quad f^{\prime}(5)=500-75+70=495\)
Then, \(\quad f^{\prime}(x)=4 x^3-3 x^2+14 x\)
\(\therefore \quad f^{\prime}(5)=500-75+70=495\)
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