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Question: Answered & Verified by Expert
If heat of dissociation of CHCl2COOH is 0.7 kcal/mole , the, ΔH for the reaction
CHCl2COOH+KOHCHCl2COOH+H2O is
ChemistryThermodynamics (C)JEE Main
Options:
  • A 13 kcal
  • B +13 kcal
  • C 14.4 kcal
  • D 13.7 kcal
Solution:
2221 Upvotes Verified Answer
The correct answer is: 13 kcal
Enthalpy of neutralization of strong acid and strong base is 13.7kcal/mol
ΔH= 13.7+0.7
=13.0kcal

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