Search any question & find its solution
Question:
Answered & Verified by Expert
If hydrogen atom is its ground state absorbs, $10.2 \mathrm{eV}$ of energy. The orbital angularmomentum is increase by
Options:
Solution:
1479 Upvotes
Verified Answer
The correct answer is:
$1.05 \times 10^{-34} \mathrm{~J} / \mathrm{s}$
Electron goes to its first excited state $(\mathrm{n}=2)$ from ground state $(\mathrm{n}=1)$ after absorbing $10.2 \mathrm{eV}$ energy
$$
\begin{array}{l}
\therefore \text { Increase in momentum }=\frac{\mathrm{h}}{2 \pi} \\
=\frac{6.6 \times 10^{-34}}{6.28} \\
=1.05 \times 10^{-34} \mathrm{~J}-\mathrm{S}
\end{array}
$$
$$
\begin{array}{l}
\therefore \text { Increase in momentum }=\frac{\mathrm{h}}{2 \pi} \\
=\frac{6.6 \times 10^{-34}}{6.28} \\
=1.05 \times 10^{-34} \mathrm{~J}-\mathrm{S}
\end{array}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.