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If in a triode value amplification factor is 20 and plate resistance is $10 \mathrm{k} \Omega$, then its mutual conductance is
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Verified Answer
The correct answer is:
2 milli mho
Mutual conductance $\mathrm{g}_{\mathrm{m}}=\frac{\mu}{\mathrm{R}_{\mathrm{P}}}$
$$
=\frac{20}{10 \times 10^{3}}=2 \times 10^{-3}=2 \text { milli mho }
$$
$$
=\frac{20}{10 \times 10^{3}}=2 \times 10^{-3}=2 \text { milli mho }
$$
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