If in the circuit, power dissipation is 150 W , then R is, 2 Ω, 6 Ω, 5 Ω, 4 Ω

Power = V 2 R 1 5 0 = V 2 R net = 15 2 R net 1 R net = 1 R + 1 2 ∴ R net = 2 R R + 2 ∴ 150 = 15 2 R + 2 2 R ∴ R = 6 Ω

If in the circuit, power dissipation is 150 W , then R is

Question: Answered & Verified by Expert

If in the circuit, power dissipation is

150 W

, then

R

PhysicsCurrent ElectricityNEET

Options:

Solution:

2788 Upvotes Verified Answer

The correct answer is:

6 Ω

Power

= \frac{V^{2}}{R}

150 = \frac{V^{2}}{R_{net}}

= \frac{15^{2}}{R_{net}}

\frac{1}{R_{net}} = \frac{1}{R} + \frac{1}{2}

∴ R_{net} = \frac{2 R}{R + 2}

∴ 150 = \frac{15^{2} (R + 2)}{2 R}

∴ R = 6 Ω

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