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If in the circuit, power dissipation is $150 \mathrm{~W}$, then $\mathrm{R}$ is
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The correct answer is:
$6 \Omega$
$6 \Omega$
$W=\frac{V^2}{R_{\text {net }}} ; 150=\frac{(15)^2}{R}+\frac{(15)^2}{2} \Rightarrow R=6 \Omega$
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