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If $\omega$ is a complex cube root of unity and $a, b, c$ are distinct real numbers, then
$$
\frac{a+b \omega+c \omega^2}{c+a \omega+b \omega^2}+\frac{a+b \omega+c \omega^2}{b+c \omega+a \omega^2}=
$$
Options:
$$
\frac{a+b \omega+c \omega^2}{c+a \omega+b \omega^2}+\frac{a+b \omega+c \omega^2}{b+c \omega+a \omega^2}=
$$
Solution:
1535 Upvotes
Verified Answer
The correct answer is:
-1
No solution. Refer to answer key.
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