If ω is a complex cube root of unity, then 1 - ω + ω 2 6 + 1 - ω 2 + ω 6 =

Question

If ω is a complex cube root of unity, then 1 - ω + ω 2 6 + 1 - ω 2 + ω 6 =, 0, 6, 64, 128

MARKS App · Accepted Answer

Given that 1 - ω + ω 2 6 + 1 - ω 2 + ω 6 We know that 1 + ω + ω 2 = 0 & ω 3 = 1 = - 2 ω 6 + - 2 ω 2 6 = 64 ω 6 + 64 ω 12 we know that ω 3 n = 1 . Required value = 64 + 64 = 128 .

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