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Question: Answered & Verified by Expert
If $\omega$ is a complex non-real cube root of unity, then $\omega$ satisfies which one of the following equations?
MathematicsComplex NumberNDANDA 2008 (Phase 1)
Options:
  • A $x^{2}-x+1=0$
  • B $x^{2}+x+1=0$
  • C $x^{2}+x-1=0$
  • D $x^{2}-x-1=0$
Solution:
2235 Upvotes Verified Answer
The correct answer is: $x^{2}+x+1=0$
If $\omega$ is cube root of unity then $\omega^{2}+\omega+1=0$ So, \omega satisfies the equaion $x^{2}+x+1=0$

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