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If $\theta$ is the polarising angle for a medium in which the speed of light is $v$, then according to
Brewster's law
Options:
Brewster's law
Solution:
1761 Upvotes
Verified Answer
The correct answer is:
$\theta=\tan ^{-1}(c / v)$
According to Brewster's law,
$$
\mu=\tan \theta_{p}
$$
where, $\mu=$ refractive index $=\frac{c}{v}$
and $\theta_{P}=$ polarising angle $=\theta$
$\therefore \quad \theta=\tan ^{-1} \mu=\tan ^{-1}\left(\frac{c}{v}\right)$
$$
\mu=\tan \theta_{p}
$$
where, $\mu=$ refractive index $=\frac{c}{v}$
and $\theta_{P}=$ polarising angle $=\theta$
$\therefore \quad \theta=\tan ^{-1} \mu=\tan ^{-1}\left(\frac{c}{v}\right)$
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