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If $\mu$ is the universal set and $\mathrm{P}$ is a subset of $\mu$, then what is $\mathrm{P} \cap(\mathrm{P}-\mu) \cup(\mu-\mathrm{P})\}$ equal to ?
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The correct answer is:
$\phi$
Since $\mu$ is universal set and $\mathrm{P} \subseteq \mu, \mathrm{P}-\mu=\phi$ and $\mu-\mathrm{P}=\mathrm{P}$
So, $(P-\mu) \cup(\mu-P)=\phi \cup P=P^{\prime}$
Now, $\operatorname{P} \cap\{P-\mu) \cup(\mu-P)\}=\operatorname{P} \cap P=\phi$
So, $(P-\mu) \cup(\mu-P)=\phi \cup P=P^{\prime}$
Now, $\operatorname{P} \cap\{P-\mu) \cup(\mu-P)\}=\operatorname{P} \cap P=\phi$
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