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If isobutane and n-butane are present in a gas, then how much oxygen should be required for complete combustion of $5 \mathrm{~kg}$ of this gas
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$17.9 \mathrm{~kg}$
Isobutane and $n$-butane $\left[\mathrm{C}_4 \mathrm{H}_{10}\right]$ have same molecular formula; $\mathrm{C}_4 \mathrm{H}_{10}+\frac{13}{2} \mathrm{O}_2 \rightarrow 4 \mathrm{CO}_2+5 \mathrm{H}_2 \mathrm{O}$
For $58 \mathrm{gm}$ of $C_4 H_{10} 208 \mathrm{gm} O_2$ is required then for $5 \mathrm{~kg}$ of $C_4 H_{10} \quad O_2=\frac{5 \times 208}{58}=17.9 \mathrm{~kg}$
For $58 \mathrm{gm}$ of $C_4 H_{10} 208 \mathrm{gm} O_2$ is required then for $5 \mathrm{~kg}$ of $C_4 H_{10} \quad O_2=\frac{5 \times 208}{58}=17.9 \mathrm{~kg}$
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