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If it is assumed that ${ }_{92}^{235} U$ decays only by emitting $\alpha$ and $\beta$ particles, the possible product of the decay is :
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The correct answer is:
${ }_{89}^{227} A c$
New mass no. $=235-2 \times 4=227$
New at. no. $=92-2 \times 2+1=92-4+1=89$
New at. no. $=92-2 \times 2+1=92-4+1=89$
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