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Question: Answered & Verified by Expert
If it is assumed that ${ }_{92}^{235} U$ decays only by emitting $\alpha$ and $\beta$ particles, the possible product of the decay is :
ChemistryStructure of AtomJEE Main
Options:
  • A ${ }_{89}^{225} A c$
  • B ${ }_{89}^{227} A c$
  • C ${ }_{89}^{230} A c$
  • D ${ }_{89}^{231} A c$
Solution:
1429 Upvotes Verified Answer
The correct answer is: ${ }_{89}^{227} A c$
New mass no. $=235-2 \times 4=227$
New at. no. $=92-2 \times 2+1=92-4+1=89$

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