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If $k_1>k_2$ are the two values of $\mathrm{k}$ such that the lines $y-3 k x+4=0$ and $(2 k-1) x-(8 k-1) \mathrm{y}-6=0$ are perpendicular, then the equation of the line passing through $\left(k_1, k_2\right)$ and having the slope $\left(\frac{k_2}{k_1}\right)$ is
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The correct answer is:
$6 x+y=0$
No solution. Refer to answer key.
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