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If kinetic energy of a body is increased by $300 \%$ than percentage change in momentum will be:
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The correct answer is:
$100 \%$
Here $P_1=\sqrt{2 m E_1}$ and $P_2=\sqrt{2 m E_2}$
$\begin{aligned}
P^{\prime} & =\sqrt{2 m\left(E+\frac{300}{100} E_1\right)} \\
& =\sqrt{2 m 4 E_1} \\
& =2 P_1
\end{aligned}$
$\begin{aligned}
P^{\prime} & =\sqrt{2 m\left(E+\frac{300}{100} E_1\right)} \\
& =\sqrt{2 m 4 E_1} \\
& =2 P_1
\end{aligned}$
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