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If $L$ denotes the inductance of an inductor through which a current $i$ is flowing, the dimensions of $L i^2$ are
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The correct answer is:
$M {L}^2 T^{-2}$
$\frac{1}{2} L i^2=$ Stored energy in an inductor $=$ $\left[M {L}^2 T^{-2}\right]$
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