Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
If L=limxπ41tanx1sin2x1+tanxπ4x3, then the value of 40L is equal to ______. If your answer is K, mark 4K as answer after rounding off to nearest integer.
MathematicsLimitsJEE Main
Solution:
1561 Upvotes Verified Answer
The correct answer is: 4
L=limxπ4tanπ4x1sin2x4π4xπ4x2
=limxπ4141-sin2xπ-4x2
=limxπ414-cos2x22π-4x-4 (applying L-Hospital rule)
=limxπ4116cos2xπ-4x
=limxπ4116-sin2x×2-4 (again applying L-Hospital rule)
=116-1-4×2L=132

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.