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Question: Answered & Verified by Expert
If l, ml<m are roots of ax2+bx+c=0, then limxaax2+bx+cax2+bx+c=
MathematicsLimitsAP EAMCETAP EAMCET 2022 (04 Jul Shift 2)
Options:
  • A aa,aR
  • B -aa, when αl,m
  • C -aa, when αl,m
  • D aa,αl,m
Solution:
1091 Upvotes Verified Answer
The correct answer is: -aa, when αl,m

Given,

l, ml<m are roots of ax2+bx+c=0,

Also we know that value of function between the roots is negative or positive depending upon the value of a,

So, when xl,m then fx=ax2+bx+c<0, if a>0 and fx=ax2+bx+c>0, if a<0

So now using the above concept we will solve the given limit,

limxαax2+bx+cax2+bx+c=-aa, when αl,m

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