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If $\lim _{x \rightarrow a} \frac{x^9+a^9}{x+a}=9$, then $a=$
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$9^{1 / 8}$
$\lim _{x \rightarrow a} \frac{x^9+a^9}{x+a}=9 \Rightarrow \frac{2 a^9}{2 a}=9 \Rightarrow a^8=9 \Rightarrow a=9^{1 / 8}$
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